b^2+35b+96=

Solution for b^2+35b+96= equation:

Simplifying
b2 + 35b + 96 = 0

Reorder the terms:
96 + 35b + b2 = 0

Solving
96 + 35b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(32 + b)(3 + b) = 0

Subproblem 1
Set the factor '(32 + b)' equal to zero and attempt to solve:

Simplifying
32 + b = 0

Solving
32 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-32' to each side of the equation.
32 + -32 + b = 0 + -32

Combine like terms: 32 + -32 = 0
0 + b = 0 + -32
b = 0 + -32

Combine like terms: 0 + -32 = -32
b = -32

Simplifying
b = -32
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-32, -3}